Ten > Heat
If a substance of mass 500g needs 7938 J of heat to increase its temperature from 100oC to 226oC, calculate its specific heat capacity.
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Solution
The required specific heat capacity of the substance is 126 J/kg-K.
Given,
mass (m) = 500 g = $\rm \frac{500}{1000} kg$ = 0.500 kg
initial temperature (T$\rm _{1}$) = 100$\rm ^{o}$C
final temperature (T$\rm _{2}$) = 226$\rm ^{o}$C
quantity of heat (Q) = 7938 J
To find: s = ?, where s is the specific heat capacity of the substance.
By using the formula for the quantity of heat, we get,
$\rm Q = ms \cdot \triangle T$
$\rm or, s = \frac{Q}{m \triangle T}$
$\rm or, s = \frac{Q}{m ( T_{2} - T_{1} )}$
$\rm or, s = \frac{7938}{0.500 \cdot (226 - 100)}$
$\rm \therefore s = 126 J/kg-K$
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