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If power of the lens used in spectacle is -3D, what is its focal length?
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Solution
To calculate the focal length of lens we use the formula:
\(\rm P \) = $\frac{1}{f}$
where \(\rm P\) = Power of lens
and, \(\rm f\) = focal length of lens
For P = -3D :
\(\rm P \) = $\frac{1}{f}$
\(\rm or,\) \(\rm f\) = $\frac{1}{P}$
\(\rm or,\) \(\rm f\) = $\frac{1}{-3}$
\(\rm or,\) \(\rm f\) = \(\rm -0.3333m \)
Hence, for lens with power of lens -3D focal length is -0.3333m or -33.33cm approximately. This indicates it is a concave lens, typically used for correcting nearsightedness.
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