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Ten > Classification of Elements
Asked by Basanta · 2 years ago

Study the given table and answer the following questions.

  1. Which element of them can form strong alkali?

    Pseudo symbol of elementsQXYZ
    Valence shell electronic configuration of elements3s$^1$3s$^2$3s$^2$3p$^1$3s$^2$3p$^5$
  2. Rearrange them in the order of lesser metallic character.
  3. Clarify an element having the least atomic radius among them with reason.

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Arpit Sundas Arpit Sundas · 1 year ago
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Solution

Identifying the given elements Q is Sodium(Na), X is Magnesium(Mg), Y is Aluminium (Al) and Z is Chlorine (Cl).

1.Ans:

 Element Q that is Sodium(Na) can from strong alkali. Sodium reacts violently with water and produces its hydroxides that is strongly basic and is known as alkali metal. 

2.Ans: 

Since metallic character of an element depends on the ease with which an electron can be removed from its valence shell, Sodium is most metallic between other given elements as it has least valency 1. 

According to this concept, arranging the given elements in the order of lesser metallic character:

         Z(Cl) (least metallic) < Y(Al)< X(Mg)< Q(Na) (most metallic)

3.Ans: 

 Atomic radius means the distance between the centre of the nucleus and the outermost shell of an isolated atom. 

Here, Z that is Chlorine(Cl) has the most electrons in its valence shells that means its nuclear charge is also high. 

As a result, its nucleus greatly attracts the electrons nearer to it. Due to this, the valence shell contracts and its atomic radius becomes least compared to other elements. 

Hence, Chlorine(Cl) i.e. element Q has the least atomic radius among them.

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