The number of secondary windings in the coil of a transformer used in a microwave oven is 10 times t

Here,

Let the number of windings in primary coil be ‘x’.

Then the number of windings in secondary coil will be ‘10x’.

Given:

Number of primary windings ( $\rm N_p$ )= $\rm x$

Number of secondary coils ( $\rm N_s$)= $\rm 10x$

Primary Voltage( $\rm V_p$ )= $\rm 220V$

Secondary Voltage( $\rm V_s$ )= ?

To find the secondary voltage obtained from the transformer, we can use the transformer voltage formula:

$\frac{ N_p}{N_s}$ = $\frac{ V_p}{V_s}$

$\rm or, $ $\frac{ x}{10x}$ = $\frac{220 }{V_s}$

$\rm or, $ $\frac{ 1}{10}$ = $\frac{220 }{V_s}$

$\rm or, $ $\rm V_s $ = $\rm 220 . 10$

$\rm or, $ $\rm V_s $ = $\rm 2220 $

Thus, the secondary voltage obtained from the transformer is 2220 V.

The number of secondary windings in the coil of a transformer used in a microwave oven is 10 times the number of windings in the primary coil. If it is connected to a source of 220 V, what is the secondary voltage obtained from the transformer?