The ratio of the number of the primary winding to the number of secondary windings of a transformer is 22:1. If an adopter with that transformer is connected to an electric circuit having a potential difference of 220 V, calculate the output voltage so obtained.
Solution
Here,
Given:
The ratio of primary windings to secondary windings is 22:1. This means:
\(\rm N_p:N_s\)= \(\rm 22:1\)
\(\rm or, \)$\frac{ N_p}{N_s}$ = $\frac{ 22}{1}$
Primary Voltage( \(\rm V_p\) )= \(\rm 220V\)
Secondary Voltage( \(\rm V_s\) )= ?
To find the output voltage obtained from the transformer, we can use the transformer voltage formula:
$\frac{ N_p}{N_s}$ = $\frac{ V_p}{V_s}$
\(\rm or, \) $\frac{ 22}{1}$ = $\frac{220 }{V_s}$
\(\rm or, \) \(\rm V_s \) = $\frac{220 }{22}$
\(\rm or, \) \(\rm V_s \) = \(\rm 10\)
Thus, the secondary voltage obtained from the transformer is 10 V.